0-50V 2A Bench powersupply

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I use the lm10 IC because it has a reference
voltage and that’s useful for dc power supply. With
two ICs can take different output voltage and
amperage. This circuit is protected from short
circuit.P2 is for controlling the current at the range

of 0-2A. Stabilize the output voltage with R4 on
negative pin on op-amp and with R2 & P1 on
positive pin.
Op-amp output controls T1 that not let ripple of
voltage.T1 increase or decrease ampere of R6 and
control the voltage of T5 & T4. Pin 1 is the
reference voltage and reference voltage is losing
some voltage on R1 that has 100uA . This current
passes through P1 too.
Vlose
p1=100uA*Rp1
This lose voltage regulate output voltage rate of
output current is compare between reference
voltage of P3 and lose voltage on R11.T3 is
protecting short circuit with R11. For reduce out put
voltage to 0v should parallel one resistor 470 ohm
in out put. Minimum voltage is 0.4v. The maximum
output voltage is fixed with R1b and should not
become over of 50v. Therefore your transformer
should give 36V, 3A with 4700uF capacitor. T6, T5,
T7 need heatsilk.
R1a = 2,2 K
R1b = read the text
R2 = 10 K
R3, R7 = 3.3 k
R4 = 390 Ohm
R5 = 47 K
R6 = 3.3 K 1Watt
R8 = 180 Ohm
R9, R10 = 0.47 Ohm 3Watt
R11 = 0.075 Ohm 2Watt
R12 = 470 Ohm
P1 = 500K liner potentiometer
P2 = 4.7 K potentiometer
P3 = 10 K potentiometer
C1 = 1nF
C2 = 10nF
C3 = 22nF
C4 = 47mF 63v electrolytic
C5 = 4700mF 80v electrolytic
T1, T2 = BC161
T3, T4 = BD141
T5 = BD241
T6, T7 = 2V3055
D1, D2 = 1N4148
D3, D4 = 1N4001
IC1, IC2 = LM10C